How to Convert Map to String in Go

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To convert a map to string in Go, convert a map to JSON “using json.Marshal() method and then convert JSON to JSON string using the string() method.”

Using json.Marshal() function and string() method

package main

import (
  "encoding/json"
  "fmt"
)

func main() {
  data := map[string]string{
    "firstName": "John",
    "lastName": "Doe",
  }

  jsonData, err := json.Marshal(data)
  if err != nil {
    fmt.Println(err)
    return
  }

  jsonString := string(jsonData)
  fmt.Println(jsonString)
}

Output

{"firstName":"John","lastName":"Doe"}

In this example:

  1. We define a map named data with some key-value pairs.
  2. We use the json.Marshal() function to convert this map to a JSON byte slice (jsonData).
  3. We then convert jsonData to a string (jsonString) and print it.

If you want to represent a map as a series of key=value pairs, with each pair on a new line and values surrounded by quotes, you’ll have to format the string representation of the map manually.

package main

import (
  "fmt"
)

func main() {
  data := map[string]string{
    "firstName": "John",
    "lastName": "Doe",
  }

  var result string
  for key, value := range data {
    result += fmt.Sprintf("%s=\"%s\"\n", key, value)
  }

  fmt.Print(result)
}

Output

firstName="John"
lastName="Doe"

Using fmt.Sprintf() method

The fmt.Sprint() function is used to convert a map to a string, but it won’t provide the exact format you have described (with each key=value pair on a new line and values surrounded by quotes). Instead, fmt.Sprint() will generate a Go-like representation of the map.

package main

import (
  "fmt"
)

func main() {
  data := map[string]string{
    "firstName": "John",
    "lastName": "Doe",
  }

  var result string
  for key, value := range data {
    result += fmt.Sprint(key, "=\"", value, "\"\n")
  }

  fmt.Print(result)
}

Output

firstName="John"
lastName="Doe"

That’s it!

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